Answer:
B:825
Step-by-step explanation:
Hopes this helps:)
Answer:
x = 4
Step-by-step explanation:
If you do not want to read the explanation go the the next part in bold
Ok so the shorter leg of the triangle is a radius of the circle. ( This is indicated by the point in the middle of the circle.) for the hypotenuse we are given one part of the length (2) The other part also happens to be a radius ( remember that a radius is a line that starts from the center of the triangle to any point of the circumference. ) Also remember that the radius is equal to 3. That being said the hypotenuse = 2+3 which equals 5.
This triangle then happens to be a right triangle. ( A triangle formed by a tangent line and a radius is a right triangle.) This means that we can use the Pythagorean theorem to solve for x.
Below here is where the work is shown
a² + b² = c². where a and b = legs and c = hypotenuse. We are given the hypotenuse (5) and a leg (3) So we plug in what we are given and solve for the missing information. 5² = 3² + b²
5² = 25
3² = 9
we would then have 25 = 9 + b²
Next we subtract 9 from each side
25 - 9 = 16
9 - 9 cancels out
Now we have 16 = b²
finally we want to get rid of the ²
To do so we take the square root of each side

we're left with b = 4 which means that x = 4
To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.
The two numbers are both 9, so its safe to say that the median is 9.
to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).
Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3
The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.
Answers is 11/9 or decimal form is 1.222 repeating
Answer:

Step-by-step explanation:
Given
Represent the volume of the cylinder with V1 and the volume of the sphere with V2
So, from the first statement: we have:

and

To solve for
, we simply substitute
for
in 




Hence, the volume of the sphere is 