What is the vertex of the quadratic equation y = - 1/3 (x + 2)^2 +5

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

Step-by-step explanation:

$\text{The vertex form of a quadratic equation:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\---------------\\\text{We have:}\\\\y=-\dfrac{1}{3}(x+2)^2+5=-\dfrac{1}{3}(x-(-2))^2+5\Rightarrow h=-2\ \text{and}\ k=5\\\\\text{therefore the vertex is:}\ (-2,\ 5)$

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Suppose y varies directly with x, and y = -4 when x = 25. What is x when y = 10? SHOW ALL YOUR WORK HERE OR YOU WON'T GET CREDIT

Stolb23 [73]

Answer:

x = -62.5

Step-by-step explanation:

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3 years ago

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4 years ago

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What is the solution to 2x^2+8x=x^2-16?<br> x=4<br> x=-2<br> х=2<br> х=4

TEA [102]

Question: What is the solution to 2x^2+8x=x^2-16?

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3 years ago

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xxMikexx [17]

Answer:

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Step-by-step explanation:

For a line to be perpendicular to another it must have the reverse reciprocal of the opposite line, to find the reverse reciprocal you take your slope, flip the numerator and denominator, and multiply it by -1.

The slope $\frac{1}{4}$ turns into $\frac{4}{1}$ and is then multiplied by -1 to become $\frac{-4}{1}$ which can be simplified down to: $-4$