Question

What is the vertex of the quadratic equation y = - 1/3 (x + 2)^2 +5

Answer 1

Answer:

(-2, 5)

Step-by-step explanation:

$\text{The vertex form of a quadratic equation:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\---------------\\\text{We have:}\\\\y=-\dfrac{1}{3}(x+2)^2+5=-\dfrac{1}{3}(x-(-2))^2+5\Rightarrow h=-2\ \text{and}\ k=5\\\\\text{therefore the vertex is:}\ (-2,\ 5)$