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3 years ago

11

2. When creating a formula for balancing a checkbook, what do you subtract from the credits? A. debits B. check numbers C. trans

actions D. dates

Computers and Technology

1 answer:

DIA [1.3K]3 years ago

5 0

I think c transitions

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I wish we could visit Paris for the holidays into exclamatory

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Answer:

wdym

Explanation:

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3 years ago

Read 2 more answers

2.4 Code Practice: Question 1

USPshnik [31]

Answer:

num = float(input("Enter a number : "))

ab = abs(num)

sqrt = float(ab ** 0.5)

print(sqrt)

Explanation:

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4 years ago

Write a static method that implements a recursive formula for factorials. Place this method in a test program that allows the us

matrenka [14]

Answer:

Written in Java

import java.util.*;

public class Main {

public static int fact(int n) {

if (n == 1)

return n;

else

return n * fact(n - 1);

}

public static void main(String[] args) {

int num;

Scanner input = new Scanner(System.in);

char tryagain = 'y';

while(tryagain == 'y'){

System.out.print("Number: ");

num = input.nextInt();

System.out.println(num+"! = "+ fact(num));

System.out.print("Try another input? y/n : ");

tryagain = input.next().charAt(0);

}

}

}

Explanation:

The static method is defines here

public static int fact(int n) {

This checks if n is 1. If yes, it returns 1

if (n == 1)

return n;

If otherwise, it returns the factorial of n, recursively

else

return n * fact(n - 1);

}

The main method starts here. Where the user can continue executing different values of n. The program keep prompting user to try again for another number until user signals for stoppage

public static void main(String[] args) {

This declares num as integer

int num;

Scanner input = new Scanner(System.in);

This initializes tryagain as y

char tryagain = 'y';

This checks if user wants to check the factorial of a number

while(tryagain == 'y'){

This prompts user for input

System.out.print("Number: ");

This gets user input

num = input.nextInt();

This passes user input to the function and also prints the result

System.out.println(num+"! = "+ fact(num));

This prompts user to try again for another value

System.out.print("Try another input? y/n : ");

This gets user response

tryagain = input.next().charAt(0);

}

4 0

3 years ago

Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur

sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

for ip in range(octet_start, octet_end):

forth_octet = forth_octet + 1

if forth_octet > 255:

forth_octet = (forth_octet % 255) - 1

third_octet = third_octet + 1

if third_octet > 255:

third_octet = (third_octet % 255) - 1

second_octet = second_octet + 1

if second_octet > 255:

second_octet = (second_octet % 255) - 1

first_octet = first_octet + 1

if first_octet > 255:

print("No more available IP!")

break

print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0

3 years ago

Use appropriate method calls from the List ADT to create the following list:

Mumz [18]

Answer:

The complete method is as follows:

public List buildList(List L) {

L.insert(30);

L.insert(23);

L.insert(19);

L.insert(4);

return L; }

Explanation:

To complete the method, we make use of the insert() function.

This inserts elements of the list into list L. However, we have to start from the last element (i.e. in descending order)

So, the explanation is as follows:

L.insert(30); --- This inserts the last element

Continue inserting in descending order

<em> L.insert(23); </em>

<em> L.insert(19); </em>

Until the first list element is inserted

L.insert(4);

This returns the filled list L

return L;

7 0

3 years ago