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daser333 [38]
3 years ago
6

If a 3-pound bunch of bananas cost $1.50, how

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

Approximately 3 bunches would equal $4.50. So you should be able to buy at least 4 bunches which would be 10 pounds

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For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed wi
8090 [49]

Explanation:

Lets interpret Z with M trials. First we have M trials, each trial can be a success or not. The number of success is called N. Each trial that is a success becomes a trial, and if it is a success it becomes a success for Z. Thus, in order for a trial to be successful, it needs first to be successful for the random variable N (and it is with probability q), and given that, it should be a success among the N trials of the original definition of Z (with probability p).

This gives us that each trial has probability pq of being successful. Note that this probability is pq independently of the results of the other trials, because the results of the trials of both N and the original definition of Z are independent. This shows us that Z is the total amount of success within M independent trials of an experiment with pq probability of success in each one. Therefore, Z has Binomial distribution with parameters pq and M.

7 0
3 years ago
hot dog buns are sold in packages of 8 and 12. taro bought 192 total buns for a party. This is represented by the function 8x +
Lelu [443]
Here is the graphical representation of the function you provide.

You can see the the points in which the line intersects each axis.

Every point in the line is a possible option for which hot dog package was bought.

For example, Taro might have bought 0 of the packages of 8, and 16 packages of 12.

or He might've bought zero packages of 12, and 24 packages of 8.

6 0
3 years ago
Triangle ABC has side lengths a= 24, b= 40, and c= 55. What is the measure of angle C? 83.6° 116.2° 23.0° 40.7°
Harlamova29_29 [7]
<h3>Answer:  116.2°</h3>

Work Shown:

c^2 = a^2 + b^2 - 2ab\cos(C)\\\\55^2 = 24^2 + 40^2 - 2*24*40\cos(C)\\\\3025 = 576 + 1600 - 1920\cos(C)\\\\3025 = 2176 - 1920\cos(C)\\\\3025 - 2176  = -1920\cos(C)\\\\849  = -1920\cos(C)\\\\-1920\cos(C) = 849\\\\\cos(C) = (849)/(-1920)\\\\\cos(C) \approx -0.4421875\\\\C \approx \cos^{-1}(-0.4421875)\\\\C \approx 116.243535748231^{\circ}\\\\C \approx 116.2^{\circ}\\\\

The first equation is one of the three variations for the Law of Cosines.

Make sure your calculator is in degree mode.

5 0
2 years ago
Please helppp (NO LINKS!!!)
n200080 [17]

Answer:

DE = 39.64840676

CE = 35.3269891

Step-by-step explanation:

SOH CAH TOA

Thus,

sin(27) = 18/DE

tan(27) = 18/CE

DE = 39.64840676

CE = 35.3269891

4 0
2 years ago
Solve for x. -2(16 - 4x) - 8 = 6(x + 2)
Amanda [17]
So...

-2(16-4x)-8=6(x+2)             Multiply
-32+8x-8=6x+12                 Add like terms
-40+8x=6x+12                    Subtract 6x from both sides
-40+2x=12                          Add 40 to both sides
2x=52                                 Divide 2 from both sides
x=26                                   Substitute to check
-2(16-4(26))-8=6((26)+2)   Add and multiply in parenthesis
-2(-88)-8=6(28)                  Multiply
176-8=168                         Subtract
168=168                          

So x=26

I hope this helps! Have a great day!
6 0
3 years ago
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