1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksanka [162]
3 years ago
7

Given that point U is the circumcenter of triangle xvz , which segments are congruent?

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

Congruent segments are line segments that have the same length. In the given figure we find that the point U is the center of the circle and the circumcenter (The point that is equidistant from each vertex of the triangle) of triangle VXZ.  

Considering the information above, we have that the following segments are congruent:

\overline{WX}\cong \overline{WV},\ \overline{VA}\cong\overline{AZ}

\overline{XY}\cong\overline{YZ}

\overline{UV}\cong \overline{UZ}\cong \overline{UX}

You might be interested in
a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar
Margarita [4]
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18  cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem: 

h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x

thus, 

Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2

thus:

x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\  \sqrt{3} }{3}=24 \sqrt{3}       (cm^2)

but x^{2} is exactly the base area, since the base is a square of sidelength = x cm.


So, the total surface area = base area + lateral area =  24 \sqrt{3}+72   cm^2


Answer: 24 \sqrt{3}+72   cm^2

4 0
3 years ago
If 4 people each make a piece of dough and every 10days from each dough make 4 more; how many will there be after 20days
lisov135 [29]
There will be 16 pieces of dough
8 0
3 years ago
Lynne used 3/8 cup of flour and 1/3 cup of sugar in a recipe.what number is a common denominator for3/8 and 1/3
Liula [17]

Ahiffggggggggggggt was the morning I was going over the

7 0
3 years ago
Read 2 more answers
What is 15/8 equal to?
yKpoI14uk [10]

Answer:

1.875

Step-by-step explanation:

i hope this helps, have a good day!

6 0
2 years ago
Read 2 more answers
What is the value of 8/9 divided by 5/12?
bulgar [2K]

Answer: 96/45

Step-by-step explanation: The answer is 96/12 because to divide fractions you reciprocate the second fraction and turn it into a multiplication problem.  

8 times 12 = 96

9 times 5 = 45

96/45

7 0
3 years ago
Read 2 more answers
Other questions:
  • One side of triangle is 4cm longer than the shortest side and 2cm shorter than the longest side the perimeter is 38cm what are t
    14·2 answers
  • What is the final balance for the investment?
    8·1 answer
  • of the 30 students in the six period Math class, eight or also in the same fourth period Science class. which can be used to det
    12·1 answer
  • How do I find the midpoint
    5·1 answer
  • The sum of two numbers is 39. The second number is 6 more than half of the first number. Let a represent the first number and le
    7·2 answers
  • I need help with this question
    12·1 answer
  • HELP!!!
    12·1 answer
  • Find the value of negative four to the third power. a. 64 b. 16. c. -64. d. -16.​
    7·2 answers
  • Multiply the additive inverse of -1/14 with the multiplicative inverse of 21/49.
    5·1 answer
  • Billie participated in a weight loss challenge at her work. She weighed 185 lbs in March and when the competition finished in Ma
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!