The offspring that will be produced in the cross would have tortoiseshell fur.
<h3>X-linked traits</h3>
In cats, the male is XY while the female is XX.
Assuming that black fur is caused by the allele B and the orange fur is caused by A
A black female will have the genotype 
An orange male will have the genotype 
Crossing the two:
x 
Offspring:
,
,
, and 
= tortoiseshell fur female
= tortoiseshell fur male
More on x-linked traits can be found here: brainly.com/question/11189684
Answer:
No
Explanation:
The spotted hyena (Crocuta crocuta Erxleben) and the lion (Panthera leo Linnaeus) are two of the most abundant and charismatic large mammalian carnivores in Africa and yet both are experiencing declining populations and significant pressures from environmental change.
Answer: The man's genotype is WwLt while the woman's genotype is wwLt.
Explanation: From the information given above, W is the allele for wide jaw, w is the allele for narrow jaw, W is completely dominant to w, L is the allele for large teeth while t is the allele for small teeth.
The man has wide jaw but his mother has a narrow jaw, since narrow jaw is recessive the man must have inherited one recessive allele for narrow jaw from his mother who has two recessive alleles for narrow jaw. Therefore since the man has wide jaw, he must be heterozygous for wide jaw (having one dominant allele for wide jaw and one recessive allele for narrow jaw), his genotype for wide jaw is therefore Ww. The man is heterozygous for teeth size, this means that he has one dominant allele for large teeth and one recessive allele for small teeth. His genotype for teeth size is Lt. Therefore the man's genotype is WwLt.
The woman has a narrow jaw, this means that she has two recessive alleles for narrow jaw (ww) and she is heterozygous for large teeth size, this means that she has one dominant allele for large teeth and one recessive allele for small teeth (Lt). Therefore, the woman's genotype is wwLt.
Hunger and thirst are considered to be internal stimuli.
Hope that helped you.