Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span> 6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0
</span><span>Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 6x2-x-4</span>
The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span>
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is <span> -1 </span>.
<span><span> -24 + 1 = -23</span><span> -12 + 2 = -10</span><span> -8 + 3 = -5</span><span> -6 + 4 = -2</span><span> -4 + 6 = 2</span><span> -3 + 8 = 5</span><span> -2 + 12 = 10</span><span> -1 + 24 = 23
</span></span>
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span><span> 6x2 - x - 4 = 0 </span>
Answer:
-2.25
Step-by-step explanation:
Since there are 4 ticks between 2 numbers, we do 1/4 = 0.25
Now we find the value:
-2.25
One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?
Ans is 42
But not sure about it
Answer:
x = 10, x = 124
Step-by-step explanation:
(5)
Since Δ JKL is isosceles then the base angles are congruent, that is
∠ LJK = ∠ LJG = 80° , thus
∠ JLK = 180 - (80 + 80) = 180 - 160 = 20
x = 20 ÷ 2 = 10
(6)
Since Δ PQR is equilateral, then each of its angles = 60°
∠QRS = 60° - 32° = 28°
Since Δ SQR is isosceles then base angles are congruent, then
∠ SQR = ∠ QRS = 28 , thus
x = 180 - (28 + 28) = 180 - 56 = 124
