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2 years ago

I NEED HELP WITH THIS PLEASE ITS DUE TONIGHT

Mathematics

2 answers:

zvonat [6]2 years ago

7 0

<h3>Answer: 6.9</h3>

==========================================

Work Shown:

(tangent)^2 = (whole secant)*(external secant)

(TU)^2 = (RT)*(ST)

(TU)^2 = (RS+ST)*(ST)

(TU)^2 = (8+4)*(4)

(TU)^2 = 48

TU = sqrt(48)

TU = 6.928203

TU = 6.9

For more info, you can search out "secant tangent chord", or something similar, and you should get to a page that describes the formula of what's going on here. This should match up fairly similarly to what lesson 3.09 is talking about.

Greeley [361]2 years ago

5 0

Answer: 9.8

TU^2= TS x TR

TU^2= 8 x 12

TU= sqrt(96) = 9.79

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