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3 years ago

I NEED HELP WITH THIS PLEASE ITS DUE TONIGHT

Mathematics

2 answers:

zvonat [6]3 years ago

7 0

<h3>Answer: 6.9</h3>

==========================================

Work Shown:

(tangent)^2 = (whole secant)*(external secant)

(TU)^2 = (RT)*(ST)

(TU)^2 = (RS+ST)*(ST)

(TU)^2 = (8+4)*(4)

(TU)^2 = 48

TU = sqrt(48)

TU = 6.928203

TU = 6.9

For more info, you can search out "secant tangent chord", or something similar, and you should get to a page that describes the formula of what's going on here. This should match up fairly similarly to what lesson 3.09 is talking about.

Greeley [361]3 years ago

5 0

Answer: 9.8

TU^2= TS x TR

TU^2= 8 x 12

TU= sqrt(96) = 9.79

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Someone please? ??? .....

Mademuasel [1]

<h3>-3/5 </h3><h3></h3><h3></h3><h2>MARK AS BRAINLIEST</h2>

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3 years ago

15 men can dig a trench of 90 m long in

jeyben [28]

Answer:

1.5 hours= 1hour and 30 minutes

Step-by-step explanation:

90÷15=6

6÷2=3

48÷16=3

3÷2=1.5

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4 years ago

Read 2 more answers

Find the distance from point $A\left(15,-21\right)$ to the line $5x+2y\ =\ 4$ . Round your answer to the nearest tenth.

Papessa [141]

The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units

Given the coordinate (15, -21) and the line 5x + 2y = 4

In order to get the point on the line 5x + 2y =4, we can a point on the line

Let x = 0

5(0) + 2y = 4

2y = 4

y = 2

The point (0, 2) is on the line.

Find the distance between the point (15, -21) and (0, 2) using the distance formula

$D=\sqrt{(2+21)^2+(0-15)^2} \\D=\sqrt{23^2+15^2}\\D=\sqrt{754}\\D= 27.46units$

Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units

Learn more here: brainly.com/question/22624745

3 0

2 years ago

Given a graph for the transformation of f(x) in the format g(x) = f(x) + k, determine the k value.

enyata [817]

Answer:

k=6

Step-by-step explanation:

The parabola that opens up and passes through (-3,-3) will have equation,

$f(x) = {x}^{2} - 12$

The parabola the opens up a d passes through (-3,3) will have equation:

$g(x) = {x}^{2} - 6$

We want to determine the value of k, for which,

$g(x) = f(x) + k$

We rewrite g(x) in terms of f(x) to get:

${x}^{2} - 6 = {x}^{2} - 12 + 6$

$g(x) \to({x}^{2} - 6 )= f(x) \to ({x}^{2} - 12 )+k \to6$

Therefore;

$g(x) = f(x) + 6$

Hence k=6

3 0

3 years ago

Use the Law of Sines to find the missing angle of the triangle.

Natasha2012 [34]

Answer:

m∠B = 70.0° (nearest tenth)

Step-by-step explanation:

<u>Sine Rule for Angles</u>

$\sf \dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c}$

(where A, B and C are the angles and a, b and c are the sides opposite the angles)

Given:

a = 13
c = 19
A = 40°

Substituting the given values into the formula to find m∠C:

$\implies \sf \dfrac{\sin 40^{\circ}}{13}=\dfrac{\sin C}{19}$

$\implies \sf \sin C=\dfrac{19\sin 40^{\circ}}{13}$

$\implies \sf C=\sin^{-1}\left(\dfrac{19\sin 40^{\circ}}{13}\right)$

$\implies \sf m \angle C=69.96086904^{\circ}$

Interior angles of a triangle sum to 180°

$\implies \sf m \angle A+ m \angle B+m \angle C=180^{\circ}$

$\implies \sf 40^{\circ} + m \angle B+69.960...^{\circ}=180^{\circ}$

$\implies \sf m \angle B=70.03913...^{\circ}$

Therefore, m∠B = 70.0° (nearest tenth)

8 0

2 years ago