X^2-4x-17 is the same as 1x^2 + (-4)x + (-17)
It is in the form y = ax^2 + bx + c where
a = 1
b = -4
c = -17
To find the value of h, we use this formula
h = -b/(2a)
h = -(-4)/(2*(1))
h = 4/2
h = 2
Plug this back into the original function to find k
k = x^2-4x-17
k = (2)^2-4(2)-17
k = 4-8-17
k = -4-17
k = -21
So we know that a = 1, h = 2 and k = -21 making
y = a(x-h)^2 + k
turn into
y = 1(x-2)^2 - 21
which is now in vertex form. The vertex is (h,k) = (2,-21)
Answer:
r = 21
Step-by-step explanation:
nth of sequence P :

: 
Answer:
C) -1
Step-by-step explanation:
(ax+3)²=36
<em>Square root both sides</em>
ax+3=6
<em>Subtract 3 from both sides</em>
ax=3
<em>Put x in</em>
-3a=3
a= -1
C) -1 would work.
Answer:
The answer is 8.1 h
Good luck!!!!!
Step-by-step explanation:
X=2/3y-4
EXPLANATION
3x-2y=-12
You take -2y to the other side
It becomes 3x=2y-12
Then you divide 3
X=2/3y
-12/3=-4
X=2/3y-4