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4 years ago

How do I simplify 12/15, 48/56, 28/36, and 15/40

Mathematics

2 answers:

gogolik [260]4 years ago

6 0

12/15 divide both by 3=4/5
48/56 divide both by 8 =6/7
28/36 divide by 4 = 7/9

15/40 divide by 5 = 3/8

Juliette [100K]4 years ago

3 0

First, Think: Which number could divided evenly between 12 and 15. Answer: 3. 12 goes into 3 four times and 15 goed into 3 five times. So, 12/15 simplified is 4/5. For #2 both 48 and 56 go into 4. Simplify that and you get 12/14. You can simplify again. Both 12 and 14 go into 2. You will get 6/7 cuz 12 goes into 2 six times and 14 goes into 2 seven times. I think you get the idea, you should be able to do the rest on your own. If you have any questions just comment bel9w :) HP this hlps

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1. 65% of what number is 5.2?

swat32

1) 65% of x=5.2
65/100 of x=5.2
0.65x=5.2
x=5.2/0.65
x=8

2) 44% of x=55
44/100 of x=55
0.44x=55
x=55/0.44
x=125

3) 50% 0f x=7.5
50/100 of x =7.5
0.5x=7.5
x=7.5/0.5
x=15

4) 100% of x =21
100/100 of x=21
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4 years ago

What is X if 5(x-6)=3(x-5)=

bixtya [17]

First you distrbut the 5 which would give you

then you distribut the 3

then you solve for x

5x-30=3x-15

5x=3x-45

2x=45

x=22.5

8 0

4 years ago

Read 2 more answers

Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu

Svetllana [295]

Answer:

Step-by-step explanation:

Hello!

You have the variable

X: Area that can be painted with a can of spray paint (feet²)

The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²

since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.

P(X>27)

First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of $P(Z$ , you have to do the following conervertion:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².

The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:

X[bar]~N(μ;δ²/n)

So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)

To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.

I hope it helps!

4 0

4 years ago

A medical researcher wants to measure the effects of a new drug on cholesterol levels using a hypothesis test. The target is a 3

maria [59]

Answer: e. test for a difference in two population means

Step-by-step explanation:

Since the researcher takes a random sample of patients and measures their cholesterol levels before and after a treatment cycle of the drug, then the two samples are matched pairs. The difference between both samples would be determined and the mean and standard deviation of this difference is calculated. This would be used to determine the test statistic.

Therefore, the type of hypothesis test that they should use is

e. test for a difference in two population means

8 0

3 years ago

A collection of nickels and dimes has a value of 1.85. The value of the dimes is 0.10 less than twice the value of the nickels.

Alekssandra [29.7K]

Step-by-step explanation:

Let n be the number of nickels and d be number of dimes.

Since we know that the value of one dime equals $0.10 and value of 1 nickel is $0.05, therefore, value of n nickels will be 0.05n and value of d dimes will be 0.10d.

We have been given that a collection of nickels and dimes has a value of 1.85.

Let us represent this information in an equation.

$0.05n+0.10d=1.85...(1)$

We have been given that the value of the dimes is 0.10 less than twice the value of the nickels.

We can represent this information in an equation as:

$0.10d+0.10=2*(0.05n)...(2)$

Therefore, our system of equations that can be used to find the number of nickels and the number of dimes is:

$0.05n+0.10d=1.85...(1)$

$0.10d+0.10=2*(0.05n)...(2)$

8 0

4 years ago