Answer:
.
See the diagram attached below.
Let the chords be AB and AC with common point A.
AD is the diameter. Join B with D and C with D to form two triangles.
We need to prove that AB=AC.
\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}
In △ABD and△ACD;
Given that ∠BAD=∠CAD−−−−(condition 1)
since AD is diameter,∠ABD=∠ACD=90
0
So ∠ADB=∠ADC−−−−−−−−(condition 2)
AD=AD (common side)−−−−−(condition 3)
So the triangles are congruent by ASA rule.
Hence AB=AC.
In a triangle, the three interior angles always add to 180°
5x + 7x + 8x = 180
20x = 180
x = 180/20
x = 9
m∠1 = 5x = 5*9 = 45°
m∠2 = 7x = 7*9 = 63°
m∠3 = 8x = 8*9 = 72°
Answer:
45°, 63° and 72°
Answer:
x= 7/ 8 is the answer
If you wanted to simplify
Table a is 3 b is 2 and c is 1
Answer:
x=16
Step-by-step explanation:
Because of Thales Intercept Theorem, AN/NG=NE/GL
NE/GL=1/2, AG=2x-9+x+7=3x-2
2x-9/3x-2=1/2
x=16
