Answer:-288 I think
Step-by-step explanation:
The shape at the top is a trapezoid with width 2 cm and lengths 4 and 8 cm.
Its area is
4+8
-------- 2 cm = 12 cm^2
2
The lower part consists of two congruent triangles. The area of a triangle is
A = (1/2)(b)(h). Here, A = (1/2) (4)(5.75) = 11.5, so the area of both triangles is 23 cm^2.
Thus, the total area is (12+23) cm^2, or 35 cm^2.
Answer:
x = 600 m
y = 1200 m
Amax = 720000 m²
Step-by-step explanation:
Let call x the smaller side of the rectangular plot and y the largest ( we assume we have one y side bounded by a river: Then
A(p) Area of the plot x*y
A(p) = x*y
And perimeter of the plot ( to be fenced ) is:
P(p) = 2*x + y = 2400 ⇒ y = 2400 - 2*x
Area of rectangular plot as function of x:
A(x) = x * ( 2400 - 2x )
Taking derivatives on both sides of the equation
A´(x) = ( 2400 - 2x ) + (-2) *x ⇒ A´(x) = ( 2400 - 2x ) - 2x
A´(x) = 0 ⇒ 2400 - 4x = 0 ⇒ 4x = 2400
x = 600 m
And y = 2400 - 2*x
y = 2400 - 1200
y = 1200 m
And the largest enclosed area is Amax = 1200*600
Amax = 720000 m²
Same as last time:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(6--1)^2+(-2-4)^2
d^2=7^2+(-6)^2
d^2=49+36
d^2=85
d=√85 (85=5*7 and both 5 and 7 are prime so √85 cannot be simplified any further)
The exact distance is √85 units.
