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Setler [38]
3 years ago
7

If the relative frequency of a train being late is 0.15, how often could you expect the train to be late in 100 days?

Mathematics
2 answers:
Natali [406]3 years ago
4 0
Relative frequency is the number of times that the train is late between the total of journeys, so only multiply 0.15*100 =15 times
VARVARA [1.3K]3 years ago
3 0

the answer would be 15 times as 0.15 x 100 = 15


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Answer:

4) 7

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4) 5x+2= 37

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3. B

Step-by-step explanation:

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59  is D 
because  with the point (-3,7) you substitute it into the equation, making it: 7=4x+b.  solve for b.  then you have y=4x+19.     work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.


60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!


61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3


62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation. 
but wait, you need a slope! 
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!



63 is  C.   y= 1/2x+3

64 is B. (3, -5)

66 is B. negative. the line  goes \ ( not / which is positive)

67 would be A. because it is positive and the I and the E are in the right places.


70 is C.  2/3.   as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3


71  is D.  y= 3x+10

72 is C. a third degree monomial

73 can't read


74 can't read 
 
75 can't read.

 
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3 years ago
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