Consider the Earth as a sphere. Think of the atmosphere as having a height of say about 20000 m. The volume of a sphere is 4/3 * pi * r ^3.
Find the volume of a sphere of radius 6020000 m and subtract the volume of the Earth which is a sphere of radius 6000000 m (approx).
This would be the volume of air in m^3.
Approximate the lungs as a cube, it would be approx 0.2m x 0.2m x 0.2 m = 0.008 m^3
Divide the volume of air around the Earth by 0.008.
0.001 m^3 of air contains about 6 x 10^23 molecules which is about 12 x 10^23 atoms.
If your lungs are 0.008 m^3 then that would be about 96 x 10 ^23 or about 10^25 atoms.
Compare that number with the earlier number when dividing air in the atmosphere by 0.008.
I hope this helps. :)
the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.
Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(
l
M
)dx The moment of inertia of small piece about the YY' axis
dl=[(
l
M
)dx]x
2
Therefore, the moment of inertia of the complete rod about the YY' axis.
b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I
CD
is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;
l
CD
=l
YY
′
+Md
2
=
12
Ml
2
+M(
2
l
)
2
l
CD
=
3
Ml
2
.........(2)
Answer:
after 6 second it will stop
he travel 36 m to stop
Explanation:
given data
speed = 12 m/s
distance = 100 m
decelerates rate = 2.00 m/s²
so acceleration a = - 2.00 m/s²
to find out
how long does it take to stop and how far does he travel
solution
we will apply here first equation of motion that is
v = u + at ......1
here u is speed 12 and v is 0 because we stop finally
put here all value in equation 1
0 = 12 + (-2) t
t = 6 s
so after 6 second it will stop
and
for distance we apply equation of motion
v²-u² = 2×a×s ..........2
here v is 0 u is 12 and a is -2 and find distance s
put all value in equation 2
0-12² = 2×(-2)×s
s = 36 m
so he travel 36 m to stop
Answer:
Same
Ben.
Explanation:
m = Mass Bonnie and Ben lift = 50 kg
s = Displacement of mass by both the students = 0.6 m
Work done by both the student is
The amount of work done by both the students will be equal to 300 J.
= Time taken by Bonnie = 1 minute = 60 seconds
= Time taken by Ben = 10 seconds.
Power delivered by Bonnie
Power delivered by Ben
So, power delivered by Ben is more.
