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xxTIMURxx [149]
3 years ago
8

The absolute magnitude of a star________.

Physics
1 answer:
serg [7]3 years ago
8 0
<span>The absolute magnitude of a star is how bright it would appear to us
if it were located ten parsecs (about 32.6 light years) from us.  So it's
a way of treating all stars equally ... on a "level playing field" ... and it
describes each star's actual brightness. </span>
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You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

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3 years ago
A physics book slides off a table at 1.25ms and hits the ground after 0.4s
tresset_1 [31]

Answer:

Whats the question here?

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3 years ago
Write down formula of power​
r-ruslan [8.4K]
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A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
Luda [366]

Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

3 0
3 years ago
What kind of weather is signaled by cumulus clouds
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