Answer:
This tells us that:
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector, .
So we can write this as:
What is the vertical asymptote of this function?
1 answer:
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Table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
<h3>What is a parabola?</h3>It is defined as the graph of a quadratic function that has something bowl-shaped.
We have the tables shown in the picture.
We know the quadratic form of a parabola is:
y = ax² + bx + c
If a > 0 the parabola opens
In the equation:
y = x² - 6x
1 > 0 the parabola opens and y-intercept is:
y = 0 (plug x = 0 in the given equation)
a = 1, b = -6, and c = 0
Thus, table (A) represents the parabola y = x² - 6x in which the parabola opens and the y-intercept is (0, 0) table (A) is the correct choice.
Learn more about the parabola here:
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