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Reil [10]
3 years ago
7

What is the vertical asymptote of this function?

Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

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Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Group 1:

μ1 = 59.7

s1 = 2.8

n1 = sample size = 12

Group 2:

μ2 = 64.7

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A.)

Null and alternative hypothesis

Null : μ1 = μ2

Alternative : μ1 < μ2

B.)

USing the t test

Test statistic :

t = (m1 - m2) / S(√1/n1 + 1/n2)

S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))

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t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)

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Decision rule :

If tstat < - tα, (n1+n2-2) ; reject the Null

tstat < t0.1,25

From t table :

-t0.1, 25 = - 1.3163

tstat = - 1.9913

-1.9913 < - 1.3163 ; Hence reject the Null

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Answer:

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Step-by-step explanation:

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