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vampirchik [111]
3 years ago
5

What is the length of the hypotenuse in the right triangle shown below?

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

Picture needed. not enough info

AysviL [449]3 years ago
5 0

Answer:

a² + b² = c², where a and b are the legs and c is the hypotenuse.

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If the length and width of a rectangle are tripled, the area of that rectangle will increase by what percentage? A) 9% B) 90% C)
shepuryov [24]
X*Y

3X*3Y =9XY

9XY/XY = 9
9*100%= 900%
7 0
3 years ago
During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?
Novosadov [1.4K]
So basically ...

You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

280 × 100 = 28,000

And then we divide,

28,000 ÷ 14 = 2000

The post office sold 2000 stamps!

Hope this helped! :)
6 0
3 years ago
The measurements of 11 fish caught during an angling competition are recorded.
stepladder [879]

Answer:

Step-by-step explanation:

A) = (35,?)

B) = POSITIVE

C) = 601

7 0
2 years ago
Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for r
butalik [34]

The missing part of the question is show in bold format.

Your teacher gives you a number cube with numbers 1-6 on its faces. You are asked to state a theoretical probability model for rolling it

once. Your probability model shows a probable outcome of 1/6 for each of the numbers on the cube, 1 chance for all any of the 6 numbers.

You roll it 500 times and get the following data:

Outcome 1 2 3 4 5 6

Frequency 77 92 75 90 76 90

Exercises 1–2

1. If the equality model was correct, about how many of each outcome

would you expect to see if the cube is rolled 500 times

2. Based on the data from the 500 rolls, how often were odd numbers observed? How often were even numbers observed?

Answer:

Step-by-step explanation:

1.

If the equally likely model was correct,  about how many of each outcome

would you expect to see if the cube is rolled 500 times.

The probability of rolling any of the numbers from 1 to 6 is  p(1/6)

The number of each of the outcomes expected to be seen in 500 rolls of the number cube is np

= 500 * \frac{1}{6}  \\ \\ = \frac{500}{6} \\ \\  = 83.333 \\ \\ \approx 83

2.  From the given data in the roll;

The odd numbers 1, 3 and 5, were obtained at  77, 75 and 76 times respectively.

Thus, the total number of times odd number were rolled = 77 + 75 + 76 = 228

Probability of an odd number turning up = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{228}{500}

= 0.456

= 45.6%

The even numbers, 2, 4 and 6, were obtained 92, 90 and 90 times respectively.

The total number of times even number were rolled = 92 + 90 + 90 = 272

Probability of an even number turning up  = \frac{ number \ of  \ required  \ outcome}{ total \  number  \ of  \ possible \ outcome}

= \frac{272}{500}

= 0.544

= 54.4%

4 0
3 years ago
Which equation matches the graph
STatiana [176]

Answer:

D. y-2=-3(x-2)

Step-by-step explanation:

8 0
3 years ago
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