Complete Question:
From a point along a straight road, the angle of elevation to the top of a hill is 33° . A distance of 200 ft farther down the road, the angle of elevation to the top of the hill is 20°. How high is the hill?
Answer:
The hill is 165.87 ft high
Step-by-step explanation:
Check the file attached below for a pictorial understanding of the question
From ΔABC
..........(1)
From ΔABD
............(2)
Equating (1) and (2)
Substitute the value of x into equation (1)
y = 165.87 ft
If x = width, and its length is twice its width...that means it is 2 times its width....so the length of the rectangle = 2x
Answer:
Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.
Hope it helps!!!
TW is a radius of this circle.
|TW| = |WQ|
SV = VQ therefore m∠WVQ = m∠WVS = 90°. The triangle QVW is the rectangular triangle.
We calculate the length of WQ using the Pythagorean theorem.
Answer: TW = √58 ≈ 7.62
Answer:
The ordered pair is a solution
Step-by-step explanation:
5x - 4y > 20
Our point is (5,0) in the format of (x, y)
This makes 5 equal to "x", and 0 equal to "y"
Now you plug it in
5(5) - 4(0) > 20
Now multiply/simplify
25 - 0 > 20
25 > 20
This statement is true, meaning the ordered pair is a solution to the equation.