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DiKsa [7]
3 years ago
8

Please solve this it's on khan academy :( oo 238

Mathematics
1 answer:
Bad White [126]3 years ago
7 0
X = 13 and the angle of A= 83
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Which equation is equivalent to y/a=b
rewona [7]
The correct answer is the second option (b)
4 0
3 years ago
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
3 years ago
I don’t get what it means by “Identify the graphs of proportional relationships.”
Ymorist [56]
C and B is proportional relationships , because the proportional relationships always start at zero and the line must be straight !
5 0
4 years ago
I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

7 0
3 years ago
What is 5 + 5 + 5 + 5 equals 550 ​
lora16 [44]

5 + 5 + 5 + 5 equals 550 ​lgjf8654

5 0
3 years ago
Read 2 more answers
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