Please solve this it's on khan academy :( oo 238

1. What is the relationship of ratios and proportions? Give an example of a proportion.

shepuryov [24]

Ratio is the comparison of sizes of two quantities of the same unit. Proportions are the equality of two ratios. A/b =c/d

3 0

3 years ago

HELP WITH ONE MORE!!!!!!!!

Alexxx [7]

Answer:

f(x + 3) = (4x + 13)/(x - 3)

Step-by-step explanation:

If f(x) = (4x + 1)/(x - 6)

then in f(x + 3)...js replace x with (x + 3)...

f(x + 3) = (4(x + 3) + 1)/(x + 3 - 6)

;f(x + 3) = (4x + 13)/(x - 3)

3 0

3 years ago

Please help cause I don’t know how to do this

zalisa [80]

Answer:

4 GB

Step-by-step explanation:

Let "g" represent the number of gigabytes of data used. Then the phone bill is computed as ...

bill = 65 + 12g

Aurora's bill is 113, so we can put that value into the equation and solve for g.

113 = 65 + 12g

48 = 12g . . . . . . subtract 65 from both sides of the equation

4 = g . . . . . . . . . divide both sides of the equation by 12

Aurora used 4 gigabytes of data in September.

_____

You can also use your mathematical reasoning to solve this problem. The total bill consists of two charges: a fixed charge of 65 and a charge that depends on data. If you subtract the fixed charge from the bill, you find that the charge that depends on data is 113-65 = 48.

The data charge is 12 times the number of gigabytes. The data charge on the bill is 48, which is 12 times 4. Then the number of gigabytes is 4.

7 0

3 years ago

Which is the equation of the graph ?

Luba_88 [7]

I think first option is that right answer

5 0

3 years ago

Read 2 more answers

The lumen output was determined for each of I = 3 different brands of lightbulbs having the same wattage, with J = 8 bulbs of ea

brilliants [131]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Lumen of a bulb of the i brand. i=3

There are 3 populations of bulbs, Brand 1, Brand 2 and brand 3.

The objective is to test if the population means are equal.

The study parameters are:

μ₁: population mean lumen of the population of light bulbs of brand 1.

μ₂: population mean lumen of the population of light bulbs of brand 2.

μ₃: population mean lumen of the population of light bulbs of brand 3.

The hypothesis is:

H₀:μ₁= μ₂= μ₃= μ

H₁: At least one of the population means is different.

To test this hypothesis, considering the given information, I'll use an ANOVA test, then the statistic is defined as:

$F= \frac{MSTr}{MSerror}$ ~ $F_{(I-1)(J-1)}$

Rejection region

This region is always one-tailed (right), the statistic is constructed as the mean square of the treatments divided by the mean square of the error, if the number of F is big, this means that the treatments have more effect over the populations. If the value of F is small, this means that there is no difference between the variability caused by the treatments and the one caused by the residues.

Since there is no significance level specified, I'll use α: 0.05

$F_{(I-1);(J-1); 1 - \alpha } = F_{2; 7; 0.95} = 19.35$

You will reject the null hypothesis when F $_{H_0}$ ≥ 19.35

To calculate the statistic value you need to calculate the Mean Square of Treatments and the Mean Square of errors:

MSTr= SSTr/DfTr = 599.5/2= 299.75

MSerror= SSerror/Dferror= 4776.3/5= 955.26

F $_{H_0}$ = $\frac{299.75}{955.26}$ = 0.31

At this level the decision is to not reject the null hypothesis.

I hope it helps!

4 0

3 years ago