Answer:
315
Step-by-step explanation:
No. of girls be g
No. of boys be b
g= 180
g/b = 4/3
b = 3g/4
b= 3(180/4)
b= 3*45
b= 135
.
Find b+g
= 135 + 180
= 315
Answer:
The exponential function to model the duck population is:
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
Step-by-step explanation:
In order to calculate the duck population you can use the formula to calculate future value:
FV=PV*(1+r)^n
FV=future value
PV=present value
r=rate
n=number of periods of time
In this case, the present value is the initial population of 415 and the rate is 32%. You can replace these values on the formula and the exponential function to model the duck population would be:
f(n)=415*(1+0.32)^n
f(n)=415*(1.32)^n, where:
x is the duck population
n is the number of years
Step-by-step explanation:
We can prove that the triangles are congruent using the SAS method.
It's given that GH and JH are congruent (S)
Angle GHF and Angle IHJ are equal since they are vertically opposite (A)
It's given that FH and HI are congruent (S)
Thus, the triangles are congruent, which implies that the remaining sides are equal.
Answer:

Step-by-step explanation:
Given the integral equation

According to integration by part;

u = x, dv = e^7x
du/dx = 1
du = dx

Substitute the given values into the formula;
