![\dfrac{-40x^3-12x^2+16x}{-4x}=\dfrac{-40x^3}{-4x}+\dfrac{-12x^2}{-4x}+\dfrac{16x}{-4x}=10x^2+3x-4](https://tex.z-dn.net/?f=%20%5Cdfrac%7B-40x%5E3-12x%5E2%2B16x%7D%7B-4x%7D%3D%5Cdfrac%7B-40x%5E3%7D%7B-4x%7D%2B%5Cdfrac%7B-12x%5E2%7D%7B-4x%7D%2B%5Cdfrac%7B16x%7D%7B-4x%7D%3D10x%5E2%2B3x-4%20)
Answer: a- 10x^2 + 3x - 4
Answer:
1/4
Step-by-step explanation:
The given info constitutes a proportion: 3 males : 1 female.
Adding 3 and 1 together, we get 4.
The fraction of students in the course who are female is then 1/4.
5/8 * 4/5
= 1/8 * 4/1
= 1/4 * 2/1
1/2 * 1/1
Final answer = 1/2
I like you manners:). eighty multiplied by one and 25 hundredths. Hope this helps! :)
X^2-7x+38=5x+3
x^2-7x+38-5x-3=5x+3-5x-3
x^2-12x+35=0
Factoring:
(x-5)(x-7)=0
Two solutions:
x-5=0→x-5+5=0+5→x=5
x-7=0→x-7+7=0+7→x=7
Answer: x=5 and x=7
Answer: Options B. 7 and D. 5