Answer:
$75 I think. Not 100% sure but like 95% sure :)
The correct answer should be last one BC=DC
The principal to be deposited is $ 11874.6594
<em><u>Solution:</u></em>
Given is a simple interest problem
Principal = ?
Simple Interest = $ 2179
![Rate = 3\frac{2}{3} \% = \frac{11}{3} \% = 3.67 \%](https://tex.z-dn.net/?f=Rate%20%3D%203%5Cfrac%7B2%7D%7B3%7D%20%5C%25%20%3D%20%5Cfrac%7B11%7D%7B3%7D%20%5C%25%20%3D%203.67%20%5C%25)
Number of years = 60 months = ![\frac{60}{12} = 5 \text{ years }](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7B12%7D%20%3D%205%20%5Ctext%7B%20years%20%7D)
<em><u>The simple interest is given by formula:</u></em>
![Simple\ Interest = \frac{p \times n \times r}{100}](https://tex.z-dn.net/?f=Simple%5C%20Interest%20%3D%20%5Cfrac%7Bp%20%5Ctimes%20n%20%5Ctimes%20r%7D%7B100%7D)
Where, "p" is the principal and "r" is the rate of interest and "n" is the number of years
![2179 = \frac{p \times 3.67 \times 5}{100}\\\\217900 = 18.35p\\\\p = \frac{217900}{18.35}\\\\p = 11874.6594](https://tex.z-dn.net/?f=2179%20%3D%20%5Cfrac%7Bp%20%5Ctimes%203.67%20%5Ctimes%205%7D%7B100%7D%5C%5C%5C%5C217900%20%3D%2018.35p%5C%5C%5C%5Cp%20%3D%20%5Cfrac%7B217900%7D%7B18.35%7D%5C%5C%5C%5Cp%20%3D%2011874.6594)
Thus the principal to be deposited is $ 11874.6594
Answer:
D
Step-by-step explanation:
Got 100%
486-9+6+33×2
477+6+33×2×
483+33×2×
483+66×
66×+483