Question

The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values for the width?

Answer 1

Answer:

  The width must be greater than 3 meters.

Step-by-step explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

  P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

  P > 36 m

  12w > 36 m . . . . . . . substitute our expression for P

  w > 3 m . . . . . . . . . . divide by 12

The possible values for width are those values that are more than 3 meters.