The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values f

Question

stealth61 [152]

2 years ago

9

The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values f

or the width?

Mathematics

1 answer:

Lostsunrise [7] · Answer 1 · 2022-09-08T12:16:03+03:00

Answer:

The width must be greater than 3 meters.

Step-by-step explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

P > 36 m

12w > 36 m . . . . . . . substitute our expression for P

w > 3 m . . . . . . . . . . divide by 12

The possible values for width are those values that are more than 3 meters.