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LiRa [457]
2 years ago
14

Find the sum. 0.52 + 716.1 A-716.62 B-627.22 C-0724.12 D-1562.82

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
7 0
The answer is A-716.62
velikii [3]2 years ago
7 0

Answer:

A.

Step-by-step explanation:

You might be interested in
If I am adding one positive number and one negative number, will the answer be positive or negative? What does it depend on?
maxonik [38]

It depends on which number has the greatest absolute value.

Think about it as money

If you owe me $10, this is shown as -10

Now  if I give you back 2 dollars  (+2), How much money do I still owe you.

The equation is -10+2

I still owe you 8 dollars which is portrayed as -8

Hope this helps :)

8 0
2 years ago
-2(11-12x)= -4(1-6x)
GalinKa [24]

The given equation -2(11 - 12x) = -4(1 - 6x) has infinite solutions

<u><em>Solution:</em></u>

Given that we have to solve the given expression

Given expression is:

-2(11 - 12x) = -4(1- 6x)

We have to use distributive property to solve the given expression

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

Which means,

a(b + c) = ab + ac

Apply this in given expression

-2(11 - 12x) = -4(1-6x)

-22 + 24x = -4 + 24x

When both sides of the equation are simplified, the coefficients are the same, then infinite number of solutions occur

If we end up with the same term on both sides of the equal sign, such as 24x = 24x, then we have infinite solutions

5 0
3 years ago
Crystal reads 25 pages in 1 hour. Write an equation to represent the 2
Inessa05 [86]

Answer:

she read 25 pages in 60 minutes

Step-by-step explanation:

8 0
3 years ago
Which of the following options have the same value as 96% of 25?
Doss [256]
A and B are correct because 96/100 is equivalent to 0.96, which is also 96%.
3 0
2 years ago
Read 2 more answers
Consider the function attached below
Masja [62]

Answer:

2

Step-by-step explanation:

Hello,

x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{2f^{-1}(x)}+5\\\sqrt{2f^{-1}(x)} =x-5\\2f^{-1}(x)=(x-5)^2\\f^{-1}(x)=\dfrac{(x-5)^2}{2}

now let's replace x by 7 it comes

f^{-1}(7)=\dfrac{(7-5)^2}{2}=\dfrac{2^2}{2}=2

hope this helps

4 0
3 years ago
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