Find the sum. 0.52 + 716.1 A-716.62 B-627.22 C-0724.12 D-1562.82

The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man

Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

$A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2$

So, the area of the floor space is equal to 5.83 sq yards.

5 0

3 years ago

Printing a newsletter cost $1.50 per copy plus $450 in printers fee. The copies are sold for $3 each. How many copies of the new

e-lub [12.9K]

1.50x + 450 = 3x
450 = 3x - 1.50x
450 = 1.50x
450/1.50 = x
300 = x

300 copies must be sold to break even

6 0

3 years ago

Read 2 more answers

The perimeter of a room is 43 ft. The width is 9 1 2ft. What is the length?

andreev551 [17]

$answer = 12 \: ft \\ solution \\ perimeter = 43 ft\\ breadth = 9 \times \frac{1}{2} = \frac{19}{2 } = 9.5 \: ft\\ now \\ perimeter \: of \: \: rectangle = 2(l + b) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: 43= 2(l + 9.5) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: 43 = 2l + 19 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: - 2l = 19 - 43 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: - 2l = - 24 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: l = \frac{ - 24}{ - 2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: l = 12 \: ft \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$

7 0

3 years ago

Read 2 more answers

ella drew a rectangle that was 3 units wide and 4 units long. Draw a different rectangle that has the same perimeter but a diffe

RUDIKE [14]

First we can find the perimeter of the given rectangle

P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14

So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length

14=2L+2*2
14=2L+4
10=2L (subtract 4 from both sides)
L=5

So the dimensions are 5 units and 2 units

Hope this helps!

5 0

3 years ago

HELP ASAP PLEASE Find the area of the figure.

WITCHER [35]

Answer:

39.82

Step-by-step explanation:

to find the entire area of the figure, you'll have to split it up into two parts:

a. triangle

b. semi-circle

therefore, the formula for the area of a triangle is 1/2(base)(height). in simpler terms, it means to multiply 1/2 by the base and the height. in this case, multiply 1/2 x 5 x 12, which gives you 60/2, which ultimately gives you 30.

to find the area of the semi circle, use the area formula for a circle and divide the area by 2. the formula is: π $r^{2}$ . so, plug in your lengths. this gives you, π(5)^2. divide this by two. you should get an answer of 9.82

finally, add your two areas (30+9.82), which equals 39.82

hope this helps!<3

4 0

2 years ago