At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

2 answers:

6 0

Everybody has two hands and u said there are 66 people's so u just have to multiply 66 with two
66
×2
----
132
there were 132 hands

velikii [3]3 years ago

4 0

This is a question that needs a bit of common sense to get to the actual answer that is desired. Firstly there is one information given .The other information has to be found from common sense. ! single handshake requires 2 people. Now we can easily determine the number of people doing 66 handshakes.
Then
The number of people required for 1 hand shake = 2
Then
The number of people required to do 66 handshakes = ( 2 * 66) people
= 132 people
Then it can be said that there were 132 people in the party. I hope the process of doing this problem is clear to you.

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Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

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In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .