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Olegator [25]
3 years ago
8

Joachim wants to win the giant monkey at the carnival game. To do so, he'll need to roll two ones with a single toss of a pair o

f number cubes. What is the probability that he will win the monkey?
Mathematics
2 answers:
andre [41]3 years ago
6 0

Solution:

we are given that

Joachim wants to win the giant monkey at the carnival game. To do so, he'll need to roll two ones with a single toss of a pair of number cubes.

As we knows that each cube has six faces and on each face we have diffrent numbers 1 through 6.

So probability of getting six on any cube=\frac{1}{6}

So probability of getting six on any cube simultaneously =\frac{1}{6}*\frac{1}{6}

The probability that he will win the monkey =\frac{1}{6}*\frac{1}{6}=\frac{1}{36}

Gemiola [76]3 years ago
4 0

\frac{1}{6}  \times  \frac{1}{6}  =  \frac{1}{36}
Answer: 1/36

Hope this helps. - M
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Step-by-step explanation:

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There are 6 rotten mangoes and 24 good mangoes in a bag. What fraction of the mangoes is rotten?
dem82 [27]

\sf \bf {\boxed {\mathbb {Given:}}}

Total number of rotten mangoes in the bag = 6

Total number of good mangoes in the bag = 24

\sf \bf {\boxed {\mathbb {To\:find:}}}

Fraction of the rotten mangoes to the total mangoes.

\sf \bf {\boxed {\mathbb {Solution:}}}

\implies {\blue {\boxed {\boxed {\purple {\sf { \frac{1}{5} }}}}}}

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation :}}}

Total number of mangoes in the bag = Total number of rotten mangoes + Total number of good mangoes

➺\:6 + 24

➺\:30

Now,

Fraction = \frac{Total \: \:   number  \:  \: of \:  \:  rotten \:  \:  mangoes}{Total  \:  \: number  \:  \: of \:  \:   mangoes}

➺\:  \frac{6}{30}

➺\:  \frac{1}{5}

Therefore, the fraction of the rotten mangoes to the total mangoes is \sf\pink{\frac{1}{5}}.

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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