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ziro4ka [17]
3 years ago
7

(3-5i)(2+9i)+(7+2i)(7-2i)

Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0
i^{2} = -1

-----------------------------------------

(3-5i)(2+9i)+(7+2i)(7-2i) = \\  \\  =  6 + 27i - 10i - 45i^{2} + 49 - 14i + 14i - 4i^{2} =  \\  \\  =55 + 17i + 45 + 4   = \boxed{104 + 17i}
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Answer:

He is the answer and btw im not sure im probably just as clueless as you so dont take my word for it.

Step-by-step explanation:

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Step-by-step explanation:

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If h(x)=(fog)(x) and h(x)=3 sqrt x+3, find g(x) if f(x) =3 sqrt x+2
Sonja [21]

Answer:

g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}

Step-by-step explanation:

Given functions: h(x) = (fog)(x)   , h(x) = 3√x + 3   and f(x) = 3√x + 2

To find: function g(x)

Consider,

(fog)(x) = h(x)

f( g(x) ) = h(x)

3\sqrt{g(x)}+2=3\sqrt{x}+3

3\sqrt{g(x)}=3\sqrt{x}+1

\sqrt{g(x)}=\frac{3\sqrt{x}+1}{3}

\sqrt{g(x)}=\sqrt{x}+\frac{1}{3}

g(x)=(\sqrt{x}+\frac{1}{3})^2

g(x)=(\sqrt{x})^2+(\frac{1}{3})^2+2\times\frac{1}{3}\times\sqrt{x}

g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}

Therefore, g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}

5 0
3 years ago
Read 2 more answers
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