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just olya [345]
3 years ago
5

2x+5y=10 x-3y=-6 how do i get the point of intersection

Mathematics
1 answer:
diamong [38]3 years ago
8 0
Multiple the second equation by 2 and subtract it from the first

2x + 5y = 10
2x - 6y = -12

now subtract

11y = 22
y = 2

Plug y = 2 in to either equation
x - 3(2) =  -6
x - 6 = -6
x = 0

The point at where they intersect is (0, 2)
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According to postal regulations, a carton is classified as "oversized" if the sum of its height and girth (the perimeter of its
Amanda [17]

Answer:

V(max) =  8712.07 in³

Dimensions:

x (side of the square base)  = 16.33 in

girth   = 65.32 in

height = 32.67 in

Step-by-step explanation:

Let

x  = side of the square base

h = the height of the postal

Then according to problem statement we have:

girth = 4*x     (perimeter of the base)

and

4* x  +  h  = 98  (at the most)   so   h = 98 - 4x  (1)

Then

V = x²*h

V = x²* ( 98 - 4x)

V(x) = 98*x² - 4x³

Taking dervatives (both menbers of the equation we have:

V´(x)  =  196 x   -  12 x²        ⇒   V´(x) = 0

196x - 12x²  = 0   first root of the equation  x = 0

Then   196 -12x = 0      12x = 196     x = 196/12

x = 16,33 in      ⇒    girth = 4 * (16.33)       ⇒ girth = 65.32 in

and from equation (1)

y = 98 - 4x       ⇒  y = 98 -4 (16,33)

y = 32.67 in

and maximun volume of a carton V is

V(max) = (16,33)²* 32,67

V(max) = 8712.07 in³

3 0
3 years ago
Can someone please explain each step in solving this?
olga_2 [115]
M(<Q) = 90; m(<P) = 12; m(<x) = 180 - 90 - 12 => m(<x) = 78.    a.
3 0
4 years ago
Read 2 more answers
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