I'm not really sure, because 650 marked down by 27% would be 474.5, which is close but not exact.
Hope I helped a little bit, sorry if I'm wrong.
If we let x as the number of years of service in the company and f(x) as the increase in the wage, the step wise function that describes the scenario is
f(x) = { 0.5, x < 3
{ 1.0, 3 ≤ x < 6
{ 1.5, 6 ≤ x < 9
{ 2.0, 9 ≤ x < 12
The point (2, 12) represents the wage increase of x < 12
To solve for the confidence interval for the population
mean mu, we can use the formula:
Confidence interval = x ± z * s / sqrt (n)
where x is the sample mean, s is the standard deviation,
and n is the sample size
At 95% confidence level, the value of z is equivalent to:
z = 1.96
Therefore substituting the given values into the
equation:
Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)
Confidence interval = 3 ± 1.59
Confidence interval = 1.41, 4.59
Therefore the population mean mu has an approximate range
or confidence interval from 1.41 kg to 4.59 kg.
Answer:
2.6 and 2.7
Step-by-step explanation:
The actual square root of 7 is 2.64 and that is between 2.6 and 2.7.
Sumi because 10452 feets are 1.997 miles
