9514 1404 393
Answer:
{587, 1}
Step-by-step explanation:
The sum will be minimized when the second number is as close to zero as is allowed. If the numbers must be positive integers, the sum is minimized when the numbers are {587, 1}.
If the numbers may be real numbers, then the values that minimize the sum are {588-, 0+}
_____
The "cost" of taking a unit from the sum 588 and assigning it to the second number is that the sum of first and 3 times the second goes up by 3. In order to minimize that sum, the second number must be minimized.
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
Answer:
4 feet of ribbon ÷ 1/3 foot riboon = 12 pockets
I think the answer is B, if not not mistaken.
Answer:
68?
Step-by-step explanation:
multiples of 5 end in 5 or 0
_ _ _
last digit has 2 choices ( 5 and 0 )
1,3,5,7,9 are odd
so tens digit has 5 choices but we see that 5 is repeated so we split into more cases
when last digit is 0, tens digit has 5 choices then hundreds digit has 8 choices so 1*5*8=40
when last digit is 5, tens digit has 4 choices and hundreds digit has 7 choices (0 can't be first digit) 1*4*7=28
40+28=68
