Answer:
a) ![[-0.134,0.034]](https://tex.z-dn.net/?f=%5B-0.134%2C0.034%5D)
b) We are uncertain
c) It will change significantly
Step-by-step explanation:
a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.
Since we assume that the variances are equal, we use the pooled variance given as
,
where
.
The mean difference
.
The confidence interval is

![= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]](https://tex.z-dn.net/?f=%3D%20-0.05%5Cpm%201.995%20%5Ctimes%200.042%20%3D%20-0.05%20%5Cpm%200.084%20%3D%20%5B-0.134%2C0.034%5D)
b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.
c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.
Answer:
187.775
Step-by-step explanation:
20.3×9.25=
187.775
Answer:
The interest rate of Jess's account was 7%
Step-by-step explanation:
A = P * (1 + rt)
A = final amount
P = initial principal balance
r = annual interest rate
t = time (in years)
Replacing with the values we know:
A = P * (1 + rt)
8,150 = 5,000 * (1 + r * 9)
8,150/5,000 = 1 + 9r
1.63 = 1 + 9r
1.63 - 1 = 9r
0.63 = 9r
r = 063/9
r = 0.07 = 7%
The interest rate of Jess's account was 7%
Answer:
i think it is b Because of how the lines are kinda bent
Do u mean d?
1.5d +3.25 = 1 +2.25d
3.25 = 1 + .75d -1.5d on both sides
2.25 = .75d subtraction 1 on both sides
3 = d divide both sides by .75