<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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![BO^2=AO^2+AB^2 \\ BO^2=3^2+4^2 \\ BO^2=9+16 \\ BO^2=25 \\ BO=5](https://tex.z-dn.net/?f=BO%5E2%3DAO%5E2%2BAB%5E2%20%5C%5C%20BO%5E2%3D3%5E2%2B4%5E2%20%20%5C%5C%20BO%5E2%3D9%2B16%20%20%5C%5C%20BO%5E2%3D25%20%20%5C%5C%20BO%3D5)
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
![\sin \angle BOA= \dfrac{AB}{BO} = \dfrac{4}{5} =0.8](https://tex.z-dn.net/?f=%5Csin%20%5Cangle%20BOA%3D%20%5Cdfrac%7BAB%7D%7BBO%7D%20%3D%20%5Cdfrac%7B4%7D%7B5%7D%20%3D0.8)
Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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![\sin \theta=-0.8](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D-0.8)
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<span>For the answer to the question above,this is a simple question.
z = (3.25-3.5)/.25= -1
p= .8413
then multiply 100 to get the percentage.
The answer will be
84.13% or 84% rounded to the whole number.
I hope my answer helped you with your problem above. Have a nice day</span>
A function that fits the following points (0,5), (2,-13) is y = 9x + 5
<h3>Equation of a line</h3>
The equation of a line in slope-intercept form is expressed as;
y =mx +b
where;
m is the slope
b is the intercept
Given the following coordinates (0,5), (2,-13)
Slope = -13-5/2-0
Slope = -18/-2
Slope = 9
Since the y-intercept is b = 5, hence the equation of the line will be y = 9x + 5
Learn more on linear regression here; brainly.com/question/25987747
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