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mixer [17]
3 years ago
9

A storm forms over the central part of the U.S. what direction will the storm move?

SAT
1 answer:
Vlad [161]3 years ago
6 0

Answer:

west to east

Explanation:

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At 900 ∘c,kc=0. 0108 for the reaction caco3(s)←→cao(s)+co2(g) a mixture of caco3, cao, and co2 is placed in a 10. 0-l vessel at
Mrac [35]

The concentration of CaCO3 increases in all cases because Q> K.

<h3>What is equilibrium?</h3>

A chemical reaction is said to have attained equilibrium when the rate of forward reaction is equal to the rate of reverse reaction. We are told that the Kc of the reaction is 0. 0108.

In the first case:

CaCO3 - 15.0 g/100g/mol/10 L = 0.015 M

CaO - 15.0 g/56 g/mol/10 L = 0.027 M

CO2 - 4.25 g/44 g/mol / 10 L = 0.0096 M

Q = [0.027] [0.0096]/0.015

Q = 0.017

Since Q > K, the concentration of CaCO3 increases

In the second case;

CaCO3 -  2.5 g/100g/mol/10 L =0.0025 M

CaO - 25.0 g/56 g/mol/10 L = 0.045 M

CO2 - 5.66 g/44 g/mol / 10 L = 0.013 M

Q = [0.045 ] [ 0.013]/[0.0025 ]

Q = 0.23

Q > K the concentration of CaCO3 increases

In the third case;

CaCO3 - 30.5 g/100g/mol/10 L =0.031 M

CaO - 25.5 g/56 g/mol/10 L =0.046 M

CO2 - 6.48 g//44 g/mol / 10 L = 0.015 M

Q = [0.046] [ 0.015]/[0.031]

Q = 0.022

Q> K hence the concentration of CaCO3 increases

Missing parts: At 900oC, Kc = 0.0108 for the reaction: CaCO3(s) <===> CaO(s) + CO2(g) A mixture of CaCO3, CaO, and CO2 is placed in a 10.0 Liter vessel at 900oC. For the following mixtures, will the amount of CaCO3 increase, decrease, or remain the same as the system approaches equilibrium? CaCO3 CaO CO2 At Equilibrium, CaCO3 will ?? 15.0 g 15.0 g 4.25 g Answer 2.5 g 25.0 g 5.66 g Answer 30.5 g 25.5 g 6.48 g Answer

Learn more about equilibrium: brainly.com/question/17960050

4 0
2 years ago
Drag the correct description under each cell structure to identify the role it plays in the cell.
JulsSmile [24]

The Nucleus stores the genetic information, the Lysosome breaks down macro-molecules, the Mitochondrion converts chemical fuel, the Ribosome synthesizes proteins and the Smooth ER serves as site of lipid synthesis.

The image for the question have been attached below.

  • The cell structures which needed to be match to its descriptions are Nucleus, Lysosome, Mitochondrion, Ribosome and Smooth ER.

The correct descriptions are as follows:

  1. The <u>Nucleus</u> is the cell structures that stores the genetic information of the cell.
  2. The <u>Lysosomes</u> is the cell structures that breaks down macro-molecules using digestive enzymes.
  3. The <u>Mitochondrion</u> is the cell structures that converts chemical fuel into packets of chemical energy that can power the cell.
  4. The <u>Ribosome</u> is the cell structures that works with mRNA to synthesize proteins.
  5. The <u>Smooth ER</u> is the cell structures which serves as the site of lipid synthesis.

Learn more about Cell Structure here

brainly.com/question/15079195

7 0
3 years ago
How many grams of sucrose, c12h22o11, must be added to 500. G of water at 100°c to change the vapor pressure to 752 mm hg?.
denpristay [2]

The mass number of sucrose that must be added to 500 g of water is 100.979 grams

To be able to solve this question, we need to use the number of moles concept and mole fraction concept.

<h3>What is the number of moles?</h3>

The number of moles is related to the mass of the substance divided by the molar mass of the substance.

From the given parameters;

The number of moles of water = mass/molar mass

  • Mass of water = 500 g
  • the molar mass of water = 18.02 g/mol

number of moles = 500 g/ 18.02 g/mol

number of moles = 27.75 moles

However,

  • the standard vapor pressure of the solvent \mathbf{P^0_{water}} = 760 mmHg
  • the vapor pressure of the solute = 752 mmHg

Using the mole concept:

\mathbf {X_{C_{12}H_{22}O_{11}} = \dfrac{n_{C_{12}H_{22}O_{11}}}{n_{H_2O}+n_{C_{12}H_{22}O_{11}}} }

By relative lowering of vapor pressure:

\mathbf{\dfrac{P^0_{H_2O} - P_{H_2O}}{P^0_{H_2O}} = X_{C_{12}H_{22}O_{11}}}

\mathbf{\dfrac{760 -752}{760} = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}

\mathbf{0.01053 = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}

\\ \\ \mathbf{0.01053 (27.75) +0.01053 (n_{C_{12}H_{22}O_{11}} ) = n_{C_{12}H_{22}O_{11}}}

\\ \\ \mathbf{0.2922075 =0.98947&#10; (n_{C_{12}H_{22}O_{11}} )}

\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) = \dfrac{0.2922075 }{0.98947}}

\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) =0.295 \ moles}

The mass of sucrose = number of moles × molar mass

The mass of sucrose = 0.295 moles × 342.3 g/mol

The mass of sucrose = 100.979 grams

Learn more about number of moles here:

brainly.com/question/13314627

8 0
2 years ago
According to the article, why is schizophrenia considered to be multifactorially inherited?
Crazy boy [7]

Schizophrenia is seen as  multifactorially inherited because it has no single cause and unknown environmental factors.

<h3>Why no single cause?</h3>

Note that Schizophrenia is seen as  multifactorially inherited because it has no single cause as it is made up of combination of genes that are gotten from both parents that are said to play a role in it.

Note that it is also due to unknown environmental factors as a lot of Experts have observed that a child often inherit a chemical imbalance present in the brain and as such can develop Schizophrenia .

Learn more about schizophrenia from

brainly.com/question/11132949

#SPJ1

6 0
2 years ago
Como habra aprendido su oficio quien se ocupa de transplantar los plantines?
valina [46]

Answer:

Generalmente, las personas que se encargan de transplantar plantines con semillas cultivadas son jardineros. Estas personas se encargan de cuidar plantas, semillas, vegetales y todos los componentes de un jardín, sea dentro de una casa o en un parque público.

Estas personas no requieren de un estudio de grado para poder ejercer su actividad laboral: generalmente, estas personas adquieren su oficio a través de la práctica, sea empezando como ayudante de un jardinero en actividad o a través de cursos de aprendizaje.

En cualquier caso, es una profesión que requiere de la actividad constante para adquirir los conocimientos necesarios que permitan perfeccionarse en el uso de las herramientas y el conocimiento de las técnicas que permitan un correcto cuidado de jardines, parques y plantaciones. Obviamente, también el estudio es importante, pero suele quedar en un segundo plano, por detrás de la experiencia laboral y la práctica en campo.

4 0
4 years ago
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