Answer:
a. 6.93 b. 5 c. 6.72 d. 3.46
Step-by-step explanation:
a. √4^2- 4(4)(-2)
Evaluate the power
√16-4×4(-2)
Multiply
√16-16(-2) = √16-(-32) = √16+32 Since 2 negatives equal a positive.
Add
√48
Find square root
√48= 6.92820323028-- rounded-- 6.93
b. √1^2-4(1)(-6)
Evaluate the power
√1-4(1)(-6)
Multiply
√1-(-24) = √1+24 Since 2 negatives equal a positive.
Add
√25
Find the square root
√25=5
c. √1^2-4(1)(-11)
Evaluate the power
√1-4(1)(-11)
Multiply
√1-(-44) = √1+44 Since 2 negative equal a positive.
Add
√45
Find the square root
√45= 6.7082039325-- rounded-- 6.72
d. √6^2-4(3)(2)
Evaluate the power
√36-4(3)(2)
Multiply
√36-24
Subtract
√12
Find the square root
√12= 3.46410161514-- rounded-- 3.46
Answer:
<em>Their masses are 100 kg and 90 kg</em>
Step-by-step explanation:
<u>Equations</u>
We'll solve the problem by setting only one variable. Let's call:
x = weight of the heavier boxer
Since the sum of the masses of both boxers is 190 Kg:
190 - x = mass of the lighter boxer.
It's given that 
of the mass of the heavier boxer is 10 kg less than the mass of the other, thus:
Operating:
Multiplying by 5:
Simplifying:
The heavier boxer's mass is 100 kg. The lighter boxer has a mass of 190-100 = 90 kg.
Their masses are 100 kg and 90 kg
C. 38.46% To get your answer you divide the number of students who liked sandwiches by total number of students in the cafeteria. Example: 10/26=.3846 which is 38.46%
