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Zigmanuir [339]

3 years ago

14

Hannah invested $540 in an account paying an interest rate of 4.7% compounded continuously. Assuming no deposits or withdrawals

are made, how much money, to the nearest hundred dollars, would be in the account after 18 years?

2 answers:

kumpel [21]3 years ago

3 0

I got $1,234 by the 18th year

alekssr [168]3 years ago

3 0

Answer:

1300

Step-by-step explanation:

did it on usatestprep

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Theresa is baaking muffins for the school bake sale. She bakes 94 muffins.Her friend Diego bakes 37 muffins.They plan to place 8

g100num [7]

Answer:

16 boxes

Step-by-step explanation:

94+37=131

131/8=16.375

This means that the most possible boxes that they can fill is 16 boxes

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You are considering a 5/1 ARM. What does the 1 represent?

puteri [66]

The answer is c

the 1 stands for how often the rate adjusts, which is every year.

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2 years ago

X-4 in word form <br> Please help!

Olin [163]

Answer:

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Step-by-step explanation:

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3 years ago

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Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

3 years ago

Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.

Lelechka [254]

8x2+8x+9
=16x+8x+9
=24x+9
Are that right

5 0

3 years ago