Answer:
{\bold{\sqrt{2} \text { and } \sqrt{8}} are the two irrational numbers, where their product 4 is the rational number
To Find:
Two irrational numbers whose product is the rational number
Solution:
A number is said to be rational number if that number is written as fraction and an irrational number cannot be written as the ratio of any two integers.
For example, square roots.
Now, we can take 2 and 8\sqrt{2} \text { and } \sqrt{8}
2 and 8
as irrational number.
By multiplying them,
2×8=16=4\sqrt{2} \times \sqrt{8}=\sqrt{16}=4
2 ×8=16=4
We know that 4 is the rational number.
like it plzz
Answer: The answer is -1/8
Step-by-step explanation:
3/4*2/3+3/4*-5/6
3 is cancelled out with 3, 4 with 2, 3 with 6
1/2-5/8
take the L.C.M
4(1)-1(5)/8
4-5/8
=-1/8
Answer:
I dont know but I can direct.
Step-by-step explanation:
The median is a middle number in a sorted, ascending or descending, list of numbers.
The quartile measures the spread of values above and below the mean by dividing the distribution into four groups.
The interquartile range describes the middle 50% of values when ordered from lowest to highest.
This would be a possible answer for the equation.
3(3)+0=9