Suppose that work hours in new zombie are 200 in year 1 and productivity is $8 per hour worked. what is new zombie's real gdp? i
1 answer:
Given that <span>work hours in new zombie are 200 in year 1 and productivity is $8
per hour worked.
The new zombie's real gdp in year 1 is given by 200 x $8 = $1,600
If work hours increase to 210 in year 2 and productivity rises to $10 per hour.
The new zombie's real gdp in year 2 is given by 210 x $10 = $2,100
The new zombie's rate of economic growth is given by
</span>
The new zombie's real gdp in year 1 is given by 200 x $8 = $1,600
If work hours increase to 210 in year 2 and productivity rises to $10 per hour.
The new zombie's real gdp in year 2 is given by 210 x $10 = $2,100
The new zombie's rate of economic growth is given by
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Answer:
Yes
Step-by-step explanation:
Given that a teacher prepares 26 tiles with 5 vowels numbered 1 and 21 consonants numbered 2.
The probability for drawing vowel =
Prob for consonant =
If number of trials is atleast 30 we can expect reliable results.
Here the results are recorded for 120 times at random.
Since number of trials is large, we can expect a reliable and accurate results representing the actual probability.
This is because more the number of trials, the less would be the margin of error i.edeviationfrom the expected probability would be minimum
Answer:
The value of x that gives the maximum transmission is 1/√e ≅0.607
Step-by-step explanation:
Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.
We need to equalize f' to 0
- k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
- 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
- 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
- ln(1/x) = x/2x = 1/2 ------- we send the natural logarithm as exp
- 1/x = e^(1/2)
- x = 1/e^(1/2) = 1/√e ≅ 0.607
Thus, the value of x that gives the maximum transmission is 1/√e.