Two years ago, Paul bought $350 worth of stock in a cell phone company. Since then the value of his stock has been increasing at
an average rate of 9 % per year . How much is the stock worth now?
2 answers:
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Answer:
Step-by-step explanation:
We are asked to find the equation of a line given a point and the slope. We will use the point-slope formula.
In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of this line is -4 and the line passes through (-2,5).
- m= -4
- x₁= -2
- y₁ = 5
Substitute the values into the formula.
We are finding the equation of the line, so we should find the slope-intercept form or y=mx+b ( where m is the slope and b is the y-intercept).We must isolate the variable y on one side of the equation.
First, distribute the -4 on the right side of the equation. Multiply each term inside the parentheses by -4.
5 is being subtracted from y. The inverse operation of subtraction is addition, so we will add 5 to both sides of the equation.
The equation of the line is y= -4x -3. The slope of the line is -4 and the y-intercept is -3.
Answer:
∠EGB and ∠AGF are congruent;
Transitive Property of Equality
Step-by-step explanation:
The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other
Vertical angles are congruent i.e their measures are equal
Look at the attached graph
Given:
AB // CD
E , G , H , F are col-linear
The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD
∵ AB and EF intersected at point G
∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem
When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent ( vertical angle theorem)
∵ AB // CD and EF is a transversal
∴ m∠AGF = m∠CHF (corresponding angles theorem)
Transitive Property of Equality: if one angle is equal to two other angles, then the two other angles are equal
Therefore, If a = b and b = c, then a = c
∵ m∠EGB = m∠AGF
∵ m∠AGF = m∠CHF
∴ m∠EGB = m∠CHF (transitive property theorem)
∠EGB and ∠AGF are congruent; Transitive Property of Equality
