Answer:
5:2
Step-by-step explanation:
Start with what the question is asking for, which is the ratio of math problems to minutes.
With ratios "to" also means ":", so you can change it to math problems : minutes.
Then, substitute the numbers for the labels. Math problems = 10 and minutes = 4, so now you have 10:4
Lastly, to simplify the ratio, find the greatest common factor, in this case 2, and divide both sides, which gives you your answer 5:2
Answer:
A, B and D are true.
Step-by-step explanation:
g (x) = x² - 4x + 3
f (x) = x² - 4x
What this means is that;
g (x) = f (x) + 3
What this implies is that the graph of g (x) is equivalent to when we shift that of f function graph up by 3 units.
Since g (x) is essentially shifting of f (x) upwards by 3 units, it means the graphs will never intersect.
It also implies that the vertex of g (x) will be above that of f (x)
Also since it only moves up and not in any other direction, both functions will still have the same line of symmetry.
Thus, options A, B and D are correct
Answer:
(0,3/2)
Step-by-step explanation:
y-y1=m(x-x1)
y-0=3/8(x- -4)
y= 3/8x+ 3/2
3/2= y intersept
(0,3/2)= second point
At first, let us solve The equation
We will subtract 4 from both sides
Then let us square both sides
Subtract 2 from both sides to get the value of x
You have two choices with 14
Which one will you choose?
To answer this you must know does this value including the domain or not
Let us try this value for x in the equation if the left-hand side equals the right-hand-side then the value is not extraneous
Since the right-hand side has the same value, so 14 is not extraneous.
So the correct answer is the third choice.
<span>23 identical packets, consisting of 1 sheet of paper and 4 crayons.
The maximum number of packets the teacher can make from 92 crayons and 23 sheets of paper is the greatest common factor of 92 and 23. And for the values of 92 and 23, the GCF is 23.
First, calculate the list of prime numbers that when multiplied together, get each number.
23 = 23
92 = 2 * 2 * 23
Look for the largest set of prime factors in common to both numbers. In this case, it's 23.
So the teach can make 23 identical activity packets. Each packet will contain (92 / 23 = 4) crayons, and (23 / 23 = 1) sheet of paper.</span>