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r-ruslan [8.4K]
3 years ago
10

A line with slope 3/8 passes through the point -4 0 find another point on the same line​

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

Answer:

(0,3/2)

Step-by-step explanation:

y-y1=m(x-x1)

y-0=3/8(x- -4)

y= 3/8x+ 3/2

3/2= y intersept

(0,3/2)= second point

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Alisiya [41]

Answer:

y = 14x

Step-by-step explanation:

Use the direct variation equation, y = kx

Plug in 7 as y and 0.5 as x, and solve for k:

y = kx

7 = k(0.5)

14 = k

Plug this into the equation:

y = kx

y = 14x

So, the equation of variation is y = 14x

4 0
3 years ago
he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower clas
Licemer1 [7]

Answer:

It is not normally distributed as it has it main concentration in only one side.

Step-by-step explanation:

So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).

So, let us begin the groupings into their different classes, shall we?

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0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.

(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.

(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31

(3). 0.4 - 0.6 : there are 2 values that falls into this category.

(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.

Class interval            frequency.

0.00 - 0.20.                   15.

0.20 - 0.40.                    2.

0.4 - 0.6.                        2.

4 0
3 years ago
A) 0.158<br> B) 15.8<br> C) 1.58<br> D) 1.625
vesna_86 [32]
D

1/8 = 0.125
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3 years ago
What is the solution to the system that is created by the equation y=-x+6 and the graph shown below
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If you were to plot the function y=-x+6, both functions meet at the point (4,2)
3 0
3 years ago
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Troyanec [42]

A

Step-by-step explanation:First, subtract

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2

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2

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

2

π

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=

h

h

=

S

−

2

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2

2

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r

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=

S

2

π

r

−

2

π

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2

2

π

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−

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