Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer:
16.25%
Step-by-step explanation:
520/3200 = 52/320 = 16.25%
Congruent= the same shape and size.
area of the rectangle before it is divided=8*(area congruent rectangle)
area of the rectangle before it is dividide=8*(5 cm²)=40 cm²
Area of the rectangle before it is dividide=40 cm²
Answer:
Step-by-step explanation:
<span>If the condition means conventional/regular rectangular piece of paper, then it is, probably,
rectangle of 8+3+3 = 14 inches wide and 3+10+3+10 = 26 inches long.</span>
