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3 years ago

And question 2 is use your knowledge of central and inscribed angles to find M.

Mathematics

1 answer:

ivanzaharov [21]3 years ago

7 0

Answer:

∠ RQS = 138°

Step-by-step explanation:

Since PR and PS are tangents to the circle, then

∠ QRP = ∠ QSP = 90°

The sum of the interior angles of PRQS = 360°

Subtract the sum of the interior angles from 360° for ∠ RQS

∠ RQS = 360° - (90 + 90 + 42)° = 360° - 222° = 138°

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Which two numbers on the number line have an absolute value of 2.75?

AysviL [449]

Answer:

2.75 and -2.75

Step-by-step explanation:

The absolute value of 2.75 is 2.75 and the absolute value of -2.75 is 2.75

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2 years ago

If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{

Elis [28]

Answer:

x = 36

Step-by-step explanation:

$x - 12\sqrt{x} + 36 = 0$

Subtract x and 36 from both sides.

$-12\sqrt{x} = -x - 36$

Divide both sides by -1.

$12\sqrt{x} = x + 36$

Square both sides.

$144x = x^2 + 72x + 1296$

Subtract 144x from both sides.

$0 = x^2 - 72x + 1296$

Factor the right side.

$0 = (x - 36)^2$

$x - 36 = 0$

$x = 36$

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

$x - 12\sqrt{x} + 36 = 0$

$36 - 12\sqrt{36} + 36 = 0$

$36 - 12\times 6 + 36 = 0$

$36 - 72 + 36 = 0$

$0 = 0$

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

6 0

3 years ago

ANSWER THIS QUESTION ASAP DONT SEND A FILE AT ALL. WHATS THE ANSWER I HAVE A TIKE LIMIT HELPP ONLY ANSWER IF YOU KNOW THE ANSWER

vfiekz [6]

Answer:reflect across

Step-by-step explanation:

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3 years ago

What is the domain of the relation?

amm1812

Domain:

{-4, -2, -1 , 1, 4}

Hope it helps

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3 years ago

Solve for e.<br> 9e + 4 = -5e + 14 + 13e

Snezhnost [94]

Answer:

17e+18

Step-by-step explanation:

9e+4=-5e+14+13e

4e+4+14+13e

17e+4+14

17e+18

4 0

3 years ago

Read 2 more answers