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OverLord2011 [107]
3 years ago
6

Express 0.3°8° in form a/b where by b#0​

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0

Answer:

0.3° = 0.3π/180

8° = 2π/45

Multiplying both

0.3π/180×2π/45

3/10π/180 × 2π/45

You will get

π/300 × π/45

= π²/13500 where a = π² b= 13500

Hope this helps.

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Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2
ella [17]

Answer:

16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8} \\

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

x^{2} +x^{8}  = x^{2+8}  = x^{10}

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}

Now for the expression (4x^{3} + 7y^{3} z^{4} )^2

Write the multiplying factors:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )

Multiply the term 4x^{3}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}

Then multiply the term 7y^{3}z^{4}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}

Simplify the exponents:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}

Add like terms:

= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}

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3 years ago
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natita [175]
I think it's the 180 one
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3 years ago
6 times -2 over 3 times 1 over 2
zepelin [54]

Answer:

The answer is -2 ❤

5 0
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