Answer:
a) 0.6561
b) 0.2916
c) 0.3439
Step-by-step explanation:
We are given the following information:
Let us treat high level of contamination as our success.
p = P(High level of contamination) = P(success) = 0.10
n = 4
The, by binomial distribution:
a) P(No high level of contamination)
We put x = 0, in the formula.
Probability that no lab specimen contain high level of contamination is 0.6561
b) P(Exactly one high level of contamination)
We put x = 1, in the formula.
Probability that no lab specimen contain high level of contamination is 0.6561
c) P(At least one contains high level of contamination)
Probability that at least 1 lab specimen contain high level of contamination is 0.3439
Answer: i think its 152x-11
Step-by-step explanation:
the question is written weird so that what i got
Answer:
Answer to the question:
Step-by-step explanation:
α= 54º
V= 66 ft/s
g= 9.8 m/s²
Vx= V * cos(54º) = 38.8 ft/s
Vy= V * sin(54º) = 53.4 ft/s
<u>PARAMETRIC EQUATIONS:</u>
x(t)= Vx * t
y(t)= Vy * t - (g * t²)/2
27.75/5 = $5.55 per book
32.16/6 = $5.36 per book
The online store is the cheapest because it has the lowest unit rate
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is
Multiply both sides by <em>r</em> :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for 
:
Then as gets arbitrarily large, the term 
will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
