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3 years ago

Find the area of the polygon.

Mathematics

1 answer:

svetlana [45]3 years ago

7 0

This is a trapezoid and the trapezoid formula is b1 plus b2/ 2 times height.

17 plus 5 is 22. Divided by 2 is 11.

Now, we have to multiply 11 by the height : 5.

11 times 5 is 55 and that is your area. 55 units squared.

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he price of apples went from $0.30 per lb to $0.90 per lb in three years. Find the rate of change of the price of apples. A) $0.

Tatiana [17]

To find the rate of change, find the total change in price and then divide it by number of years over which it changed. So the answer is $0.603 which is $0.20 per pound per year.

3 0

3 years ago

Read 2 more answers

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

Find the area of the base B

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

Find the perimeter of the base P

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

Find the surface area

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago

The day's high temperature in St. Louis comma Missouri was recorded as 77 degrees' F. Use the formula Upper C=5/9(F-32) to writ

ludmilkaskok [199]

Answer:

The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

Step-by-step explanation:

The day's high temperature in St. Louis ,Missouri was recorded as 77 degrees F.

We are supposed to find the day's high temperature written as degrees Celsius.

Formula : $C=\frac{5}{9}(F-32)$

Substitute the value of F is 77 degrees

So, $C=\frac{5}{9}(77-32)$

$C=\frac{5}{9}(45)$

C=25

Thus, The day's high temperature written as degrees Celsius is 25 degrees' Celsius.

6 0

3 years ago

What is the solution of the inequality x/3 > 1?

Alika [10]

If you would like to know what is the solution of the inequality x/3 > 1, you can calculate this using the following step:

x/3 > 1 /*3
x > 1 * 3
x > 3

The correct result would be x > 3.

6 0

3 years ago

How would you solve these 2 maths problems?

sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = $(-2)^{4}$ + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = $(-2)^{4}$ + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0

3 years ago