Answer:
(x − 4)² + (y − 3)² = 25
Step-by-step explanation:
The equation of a circle is:
(x − h)² + (y − k)² = r²
Given three points on the circle, we can write three equations:
(1 − h)² + (7 − k)² = r²
(8 − h)² + (6 − k)² = r²
(7 − h)² + (-1 − k)² = r²
Expanding:
1 − 2h + h² + 49 − 14k + k² = r²
64 − 16h + h² + 36 − 12k + k² = r²
49 − 14h + h² + 1 + 2k + k² = r²
Simplifying:
50 − 2h + h² − 14k + k² = r²
100 − 16h + h² − 12k + k² = r²
50 − 14h + h² + 2k + k² = r²
Subtracting the first equation from the second and third equations:
50 − 14h + 2k = 0
-12h + 16k = 0
Solving the system of equations, first reduce:
25 − 7h + k = 0
-3h + 4k = 0
Solve with substitution or elimination. Using substitution, solve for k in the first equation and substitute into the second.
k = 7h − 25
-3h + 4(7h − 25) = 0
-3h + 28h − 100 = 0
25h = 100
h = 4
k = 7h −25
k = 7(4) − 25
k = 3
Now plug these into any of the original three equations to find r.
(1 − h)² + (7 − k)² = r²
(1 − 4)² + (7 − 3)² = r²
9 + 16 = r²
25 = r²
The equation of the circle is:
(x − 4)² + (y − 3)² = 25
Graph: desmos.com/calculator/ctoljeqhnp
Answer:
5
Step-by-step explanation:
No spaces? like t h i s? or like thiiiss??? is this bugging you ????
anyway
use elimination
multiply secn equation by -1
-3x-2y=-6
add to other equation
-3x-2y=-6
<u>4x+2y=10 +</u>
1x+0y=4
x=4
sub back to solve for y
3x+2y=6
3(4)+2y=6
12+2y=6
minus 12 both sides
2y=-6
divide 2
y=-3
(4,-3)
X int can be found by subbing in 0 for y and solving for x
9x - 7y = 21
9x - 7(0) = 21
9x = 21
x = 21/9 which reduces to 7/3...so the x int is 7/3 or (7/3,0) <==
to find the y int, sub in 0 for x and solve for y
9x - 7y = 21
9(0) - 7y = 21
-7y = 21
y = -21/7
y = -3....so the y int is -3 or (0,-3) <==