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seropon [69]
3 years ago
12

Find the area of EBCD using (a) and (b).

Mathematics
1 answer:
ioda3 years ago
6 0

I hope this helps you

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1. The Marcus family drove across the country last summer and traveled 7,895 miles. The summer before they also drove across cou
MArishka [77]

Answer:

im just answering because my name is marcus.

Step-by-step explanation:

-56.3015% change

56.3015% decrease

8 0
3 years ago
If K is the midpoint of JL, JK = 8x+11 and KL = 14x-1, find JL.
gladu [14]

Step-by-step explanation:

Since, K is the midpoint of JL.

\therefore \: JK = KL \\ 8x + 11 = 14x - 1 \\ 11 + 1 = 14x - 8x \\ 12 = 6x \\  \frac{12}{6}  = x \\ 2 = x \\  \\  \because \: JL = JK + KL \\   \therefore \: JL = 8x + 11 + 14x - 1 \\ \therefore \: JL = 8x + 14x + 11 - 1 \\ \therefore \: JL = 22x + 10\\  \therefore \: JL = 22 \times 2 + 10..(plug \: x = 2) \\  \therefore \:JL = 44 + 10 \\  \huge \red{ \boxed{\therefore \:JL = 54}}

7 0
3 years ago
Read 2 more answers
Given the parent functions f(x)=3x+2 and g(x)=5^x-10,what is g(x)-f(x)?
Stels [109]
-3x + 5^x - 8 is what it is simplified so thats your final answe :}
4 0
3 years ago
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
The sum of 2 numbers is 10 the difference is 6 what are the numbers calculator
IgorLugansk [536]
8 & 2

8+2 = 10

8-2 = 6
3 0
3 years ago
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