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pochemuha
3 years ago
12

Simplify: (c+4/c^2+5x+6)/(3c^2+12c/2c^2+5c-3)

Mathematics
1 answer:
juin [17]3 years ago
6 0
(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c
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djyliett [7]

Answer:

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Step-by-step explanation:

1/3 * 3x + 5.2y

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babunello [35]

Answer:

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And solving we got:

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We can find the sings of the second derivate on the following intervals:

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Step-by-step explanation:

For this case we have the following function:

y= x^4 -36x^2

We can find the first derivate and we got:

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In order to find the concavity we can find the second derivate and we got:

y'' = 12x^2 -72

We can set up this derivate equal to 0 and we got:

y'' =12x^2 -72=0

And solving we got:

x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}

We can find the sings of the second derivate on the following intervals:

(-\infty Concave up

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x=\sqrt{6}, y=-180 inflection point

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Answer:

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