Ask question

Ask question

All categories

3 years ago

12

Simplify: (c+4/c^2+5x+6)/(3c^2+12c/2c^2+5c-3)

1 answer:

juin [17]3 years ago

6 0

(c+4/c^2+5c+6)/(3c^2+12c/2c^2+5c-3)= (c+4)/(c^2+5c+6) Multiplied by (2c^2+5c-3)/3c^2+12c= 2c^3+5c^2-3c+8c^2+20c-12/3c^4+12c^3+15c^3+60c^2+18c^2+72= 2c^3+13c^2+17c-12/3c^4+27c^3+78c^2+72c

You might be interested in

Express the given statement in the form of expression. 5 subtracted from three times any number, use t to represent any number.

oee [108]

Answer:(3-5)t

Step-by-step explanation:

You solve the equation inside of parentheses first. Then if there’s no symbol by the parentheses you multiply the answer from inside the parentheses, by the number outside. In this case the number outside, is represented by “t”

3 0

3 years ago

Read 2 more answers

Evaluate − 3 w − 5 p for w = − 4 and p = − 3

zmey [24]

Answer:

27

Step-by-step explanation:

Given

- 3w - 5p ← substitute w = - 4 and p = - 3 into the expression

= - 3(- 4) - 5(- 3 )

= 12 + 15

= 27

4 0

3 years ago

Giving 100 points for anyone who works the entire page.

xeze [42]

Answer:

It’s not 100 points btw

Step-by-step explanation:

Just do scan and solve

4 0

3 years ago

Widths of two similar rectangles are 21ft and 18ft. What is the ratio of the perimeter? Of the areas?

ad-work [718]

Ratio of perimeters is a : b:

21:18

Which reduces to: 7:6

Ratio of areas is a^2 : b^

2:

"7 ^2: 6^2"

Which simplifies to: 49:16

The answer is 7:6 and 49:36

6 0

3 years ago

The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

x = 4500

$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

p = $45

6 0

4 years ago