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notka56 [123]
3 years ago
5

HELP IN THIS QUESTION

Mathematics
2 answers:
dybincka [34]3 years ago
8 0
The answer would be 2/9
Shalnov [3]3 years ago
7 0
The answer is 2/9 of a gallon.
Because 2/9 x 9 (people) is 2 (gallon)
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The weight of a boy was 15kg last year. If his weight increases by 3kg this year, find the percentage increase in his weight.
WARRIOR [948]
This year = 18kg
18 x .3= 5.4
The percentage change would be 5.4%. If it needs to be rounded by the nearest tenth, then it would be 5%.
I’m pretty confident this is the answer but I’m not 100% sure. I hope this helps!
4 0
2 years ago
g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
I don't understand. Please help answer questions!!!!!!
insens350 [35]
16) yes, they are reflections on a summit.
17) no parallelogram shown to answer question <span />
7 0
3 years ago
{(2,17) (-7,-4) (-4,3) (0,3)} is not a function when which ordered pair is added?
Mama L [17]
I think they all will make it a function.
7 0
3 years ago
A student was assigned to read a book over 5 days. On the first day, she read 25 pages. On the second day she read 45 pages, on
nignag [31]

Answer:

Hint : They are a all common factors of 5

Step-by-step explanation:

You divide each of them by 5 then add them all together then you will get your answer.

Good luck!

7 0
2 years ago
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