1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paraphin [41]
3 years ago
9

How do you solve -26d = -364?

Mathematics
2 answers:
Novay_Z [31]3 years ago
6 0
You simply divide -364 by -26 so d=14
hope this helps! :D
gogolik [260]3 years ago
5 0
<span>-26d = -364
Divide both sides by -26 so that the only thing remaining on the left side is the variable d. Also, take into mind that when you multiply or divide a negative number by another negative number, it creates a positive number as the resultent.
Final Answer: d = 14</span>
You might be interested in
Hhhhhhhhhhhhhhhheeeeeeeeeeeeeeeelllllllllllllllllllllppppppppppppp
m_a_m_a [10]
Literally whatever number is in the parenthesis, if it’s negative like -4 then you could down 4 lines of squares and put a dot. if it’s positive then go up
7 0
2 years ago
Read 2 more answers
Two cars start at the same point. One travels north at 65 km/h and the other travels east at 50 km/h. How far are they apart aft
Kisachek [45]

Answer:

they travel 115 km/h long

4 0
2 years ago
Find one counter example to show that the conjecture is false. angle 1 and angle 2 are​ supplementary, so one of the angles is a
Mrac [35]

Answer:

B. m ∠ 1 = 90° and m ∠ 2 = 90°

Step-by-step explanation:

For most situations, the conjecture would probably be true, but there is one exception that makes this statement false.

When two right angles are supplementary, none of them is acute.

For an angle to be acute it needs to be lesser than 90°, and for a pair of angles to be supplementary they should add up to exactly 180°.

With a pair of right angles (90° each), their sum adds up to 180° but neither of them are acute.

Therefore, the answer is B. m ∠ 1 = 90° and m ∠ 2 = 90°

4 0
3 years ago
Which graph most likely shows the experimental probability histogram of X based on 100 data points?
Archy [21]

Answer:

  see attached

Step-by-step explanation:

Based on 100 trials, we don't expect the experimental probability to deviate much from the theoretical probability. The scales on the attached graphs are hard to read, but you want to choose the graph that ...

  • has bars that total 100 in their length
  • has bars that are approximately .50, .25, .17, .08 in height, corresponding to the area fraction

We think the appropriate choice may be C, but we cannot tell for sure.

3 0
2 years ago
Init. Cantian Sinaniiieeintroduction
tatuchka [14]

Answer:

The independent variable is the amount of miles walked, and the dependent is the total from home.

Step-by-step explanation:

4 0
3 years ago
Other questions:
  • Sarah's parents started a savings account for her when she was 12. The plan her parents chose earns 3.2% each year, and her pare
    9·1 answer
  • Which of the following is a coefficient in the algebra expression 12p^5+r-16?
    8·1 answer
  • A student must leave for campus in 10 mins or he will be late for class. Unfortunately he is snowed in. He can shovel the drivew
    7·1 answer
  • Someone please help me
    14·1 answer
  • Find the difference. Simplify. Combine Like Terms.
    10·1 answer
  • What is the circumference of the following circles? r=5 what is the units? _____Units​
    12·1 answer
  • Brand want to buy flowers for his friend with $33. The daisies are $1 each and the roses are $2 each. He buys 3 more daisies tha
    10·2 answers
  • Find the slope between the following points, show all work. (5, -9) and (-9, -5)
    13·2 answers
  • The population of a small town can be described by the equation PN equals 4000+70n. Where n is the number of years after 2005. E
    6·1 answer
  • I need HELP, I'm just a dumb kid from Minnesota, I have no clue what to do...The line below has a slope of 2. Both points are on
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!