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3 years ago

7

A traingle has a perimeter of 22 centimeters with a side of 7 centimeters with a side that is 7 centimeters long. the lengths of

the remaining 2 sides have a ratio of 2:3. what is the length in centimeters, of the shortest side of the triangle?

1 answer:

Leokris [45]3 years ago

3 0

The shortest side of the triangle is 10cm

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100 PTS:Please help me now plz plz

Alex Ar [27]

Answer:

x = 12

Step-by-step explanation:

We have a right triangle with hypotenuse 10 and the height 8. Either the one on the left or the one on the right

We can find the base using the Pythagorean theorem

a^2 + b^2 = c^2

a^2 +8^2 = 10^2

a^2 +64 = 100

Subtract 64 from each side

a^2 = 100 -64

a^2 = 36

Take the square root of each side

a = 6

Now a is 1/2 of the total base of the big triangle. It is identical since the triangles are equal

x = 2 * a

x = 2*6 = 12

4 0

2 years ago

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What is 0.75 in a fraction lowest terms?

kompoz [17]

0.75 = 3/4

3/4 is your anwer

3 0

3 years ago

To wash a window that is 8 meters off the ground, Stanley leans a latter against the side of the building The base of the latter

diamong [38]

Answer:

the latter is ten meters long

Step-by-step explanation:

its just ten meters long

3 0

3 years ago

Mr. Black is flying a kite above a field on a 65 foot string. The angle of elevation of the kite is 70 degrees. How high is the

Elan Coil [88]

Answer:

The correct answer is 61.08 foot.

Step-by-step explanation:

Length of the string of the kite, Mr. Black is flying is 65 foot. Thus the length between the kite and Mr. Black is given by 65 foot.

Angle of elevation is 70°.

We need to calculate the height of the kite above Mr. Black's head. The height is given by finding the sine of the angle of elevation.

Let the height be x foot.

Thus sin 70° = $\frac{x}{65}$

⇒ x = sin 70° × 65

⇒ x = 61.08

Thus the height of the kite above Mr. Black head is 61.08 foot.

6 0

3 years ago

An ice cream cone is filled with a vanilla and chocolate ice cream at a ratio of 2:

nirvana33 [79]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad 
\begin{cases}
r=radius\\
h=height\\
----------\\
diameter=2\\
r=\frac{diameter}{2}\\
\quad = 1\\
h=6
\end{cases}\implies V=\cfrac{\pi\cdot 1^2\cdot 6}{3}
\\\\\\
V=2\pi \\\\
-------------------------------$

$\bf \cfrac{\stackrel{vanilla}{volume}}{\stackrel{chocolate}{volume}}\qquad 2:1\qquad \cfrac{2}{1}\implies \cfrac{2\cdot \frac{V}{2+1}}{1\cdot \frac{V}{2+1}}\implies \cfrac{2\cdot \frac{2\pi }{2+1}}{1\cdot \frac{2\pi }{2+1}}
\\\\\\
\cfrac{2\cdot \frac{2\pi }{3}}{1\cdot \frac{2\pi }{3}}\implies \cfrac{\quad \frac{4\pi }{3}\quad }{\frac{2\pi }{3}}$

3 0

3 years ago

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